Atomistry » Phosphorus » Energy
Atomistry »
  Phosphorus »
    Energy »

Phosphorus Ionization Energy

The Phosphorus Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Phosphorus.
P -> P+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Phosphorus is:
PN+ -> P(N+1)+ + e-

Ionization Energy

P -> P1+ = 1011.7 kJ/mol = 242.03 Kcal/mol
P1+ -> P2+ = 1903.2 kJ/mol = 455.31 Kcal/mol
P2+ -> P3+ = 2912 kJ/mol = 696.65 Kcal/mol
P3+ -> P4+ = 4956 kJ/mol = 1185.65 Kcal/mol
P4+ -> P5+ = 6273 kJ/mol = 1500.72 Kcal/mol
P5+ -> P6+ = 21268 kJ/mol = 5088.04 Kcal/mol
P6+ -> P7+ = 25397 kJ/mol = 6075.84 Kcal/mol
P7+ -> P8+ = 29854 kJ/mol = 7142.11 Kcal/mol
P8+ -> P9+ = 35867 kJ/mol = 8580.62 Kcal/mol
P9+ -> P10+ = 40958 kJ/mol = 9798.56 Kcal/mol

Last articles

Hg in 6IQV
Hg in 6L8O
Hg in 6BZI
Hg in 6KIS
Hg in 6K9C
Hg in 6I3E
Hg in 6I2F
Hg in 6I1U
Hg in 6I0W
Hg in 6HXD
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy